1. Glucose levels in patients free of diabetes areassumed to follow a normal distribution with a mean of120 and a standarddeviation of 16. What proportion of patients has glucose levels exceeding 115?

2. The mean total cholesterol level in women freeof cardiovascular disease is 205 with a standard deviation of 19.2. Whatproportion of women has total serum cholesterol levels exceeding 200?

3. The gestation period for human births can betaken as normally distributed with a mean of 266 days and a standard deviationof 16 days. If a gestation period of 276 days, what percentile among humanbirths is this?

4. Suppose that the probability of a child livingin urban area in the US is obese is 20%. A social worker sees 15 childrenliving in urban areas. What is the probability that none are obese?

5. Approximately 30% of obese patients developdiabetes. If a physician sees 10 patients who are obese, what is theprobability that half of them will develop diabetes?

6. The following data was collected in survey of 8thgraders and summarize their cell phone status.

No of cell phone

Conventional Cell phone user

Smart Phone user

Total

Boys

55

65

35

155

Girls

31

78

27

136

Total

86

143

62

291

What proportion of the 8th graders hasconventional cell phones?

7. BMI in children is approximately normallydistributed within a mean 24.5 and standard deviation 6.2. A BMI between 25 and30 is considered overweight. What proportion of children is overweight?

8. The following table shows a distribution of BMIin children living US and European urban neighborhoods. (The data is inmillions.)

Neighborhood

Normal weight

Overweight

Obese

Total

US

125

50

40

215

Europe

101

42

21

164

Total

226

92

61

379

If a child is selected at random,

a. What is the probability they are overweight?

b. What is the probability that a child living inthe US urban neighborhood is overweight?

9. The risk of hepatoma among alcoholics withoutcirrhosis of the liver is 24%. Suppose we observe 7 alcoholics withoutcirrhosis. What is the probability that exactly 1 of these 7 people havehepatoma?

10.

Screening test

Impaired Glucose Tolerance

Not Impaired

Positive

17

13

Negative

8

37

A new non-invasive screening testis proposed that is claimed to be able to identify patients with impairedglucose tolerance based on a battery of questions related to health behaviors.The new test is given 75 patients. Based on each patient’s responses to thequestions they are classified as positive, or negative for impaired glucosetolerance. Each patient also submits a blood sample and their glucose tolerancestatus is determined. The results are tabulated below.

a. What is the sensitivity of the screening test?

b. What is the false positive fraction of thescreening test?

11. Thefollowing table shows the results of a screening test hypothesized to detectpersons at risk of side effects of a cosmetic surgery.

Side Effects Positive

Side Effects Absent

Total

Screen Positive

12

6

18

Screen Negative

85

204

289

Total

97

210

307

a. Compute the sensitivity of the test

b. Compute the specificity of the test

c. Compute the false positive fraction

d. Compute the false negative fraction

12. The following table shows the results of the ascreening test hypothesized to identify persons at risk for rare blood disease

No Disease

Disease

Total

Screen Positive

1274

28

1302

Screen Negative

51

45

96

Total

1325

73

1398

a. Compute the sensitivity of the test

b. Compute the specificity of the test

c. Compute the false positive fraction

d. Compute the false negative fraction